Apparently:
$$
E[X^2] = 1^2 cdot frac{1}{6} + 2^2 cdot frac{1}{6} + 3^2cdotfrac{1}{6}+4^2cdotfrac{1}{6}+5^2cdotfrac{1}{6}+6^2cdotfrac{1}{6}
$$
where $X$ is the result of a die roll.
How come this expansion?
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Best Answer
There are various ways to justify it.
For example, it follows from the definition of expectation and the law of the unconscious statistician.
Or consider the case $Y=X^2$ and computing $E(Y)$.