Solved – F stats for post hoc test of a linear mixed effects model

I have an unbalanced linear mixed effects model with three fixed factors of various levels and one random factor for my repeated measures data (for details see here).
Thanks to your help I managed to do post-hoc tests on the significant interaction terms using lsm from the lsmeans package. However, I need to report the F statistic (F value and degrees of freedom) for these post-hoc tests and wonder how???

Here is what I do:

  1. Model comparison using anova() resulting into the final model
    model_final, which reads:

    sc ~ time + cond + place + time:cond + cond:place + (1|ID), data) .

  2. I analyze the significant interaction time:cond using lsmeans:

    posthoc_1 <- glht(model_final, lsm(pairwise ~ cond|time)


and get sth like below for each level of time, here is the example for time1.

> Note: df set to 268  > > $`time = time1` >  >    Simultaneous Tests for General Linear Hypotheses >  > Fit: lme4::lmer(formula = sc ~ time + cond + place + time:cond + cond:place + (1|ID), data) >  > Linear Hypotheses: >                    Estimate Std. Error t value Pr(>|t|)  > cond1 - cond2 == 0   3.1867     0.6797   4.688 4.39e-06 *** 

This gives me t-values for the various levels of the interaction terms and their corresponding p-value, but no F stats!

My questions:

  1. Is there any way of obtaining the F stats? (F value and degree of
  2. Or am I stuck with the t-values? If so, is t(0.095;268) =
    4.588, p < 0.001 reporting the correct degrees of freedom?

If you use the lsmeans function directly rather than via glht, you might have better luck.

library(lsmeans) ( mod.pairs = contrast(lsmeans(model_final, ~ cond|time), "trt.vs.ctrl1") ) 

At this point, what you have is pairwise comparisons at each time. Is it the cond:time interaction you want to test? If so, compute contrasts of the above differences (column labeled contrast):

inter.con = contrast(mod.pairs, "trt.vs.ctrl1", by = NULL) test(inter.con, joint = TRUE) 

I'm suggesting using trt.vs.ctrl1 contrasts because it makes the right number of contrasts to match the d.f. However if you use pairwise instead, it will give the same results (it will just have to work harder).

PS this does require the latest version of lsmeans (2.12) because the joint option was not avaialble before then.

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